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Question

If S=exāˆ’sinx, find d2Sdx2

A
ex+cosx
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B
exsinx
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C
ex+sinx
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D
excosx
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Solution

The correct option is C ex+sinx
Given, S=exsinx
d2Sdx2 d(dSdx)dx
So, we have dSdx=d(exsinx)dx
dexdxdsinxdx=excosx
Thus, d2Sdx2=d(excosx)dx
dexdxdcosxdx=ex+sinx

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