Question

If ${}^{\prime }{s}^{\prime }$ is the shear strength, ${}^{\prime }{c}^{\prime }$ and $\Phi$ are shear strength parameters, and ${}^{\prime }{\sigma }_n^{\prime }$ is the normal stress at failure, then Coulomb's equation for shear strength of the soil can be represented by

• A. $c=s+{\sigma }_{n}tan\Phi$
• B. $c=s-{\sigma }_{n}tan\Phi$
• C. $s={\sigma }_n+ctan\Phi$
• D. $s=c+{\sigma }_{n}tan\Phi$

Answer 1

The correct option is B $c=s-{\sigma }_{n}tan\Phi$

$s=c+{\sigma }_{n}tan\Phi \text{[Coulomb's equation]}$
$\therefore c=s-{\sigma }_{n}tan\Phi$