wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If sn=cos(nπ10),n=1,2,3,....., then the value of s1s2...,s10s1+s2+.....+s10 is equal to

A
12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
32
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
22
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
E
1/2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is E 0
sn=cos(nπ10)
s5=cos(π2)=0
So equation s1s2...,s10s1+s2+.....+s10=s5×s1s2..,s4,s6..,s10s1+s2+.....+s10
s5×s1s2..,s4,s6..,s10s1+s2+.....+s10=0
Hence answer is D

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Angle and Its Measurement
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon