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Question

If sn=cos(nπ10),n=1,2,3,....., then the value of s1s2...,s10s1+s2+.....+s10 is equal to

A
12
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B
32
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C
22
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D
0
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E
1/2
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Solution

The correct option is E 0
sn=cos(nπ10)
s5=cos(π2)=0
So equation s1s2...,s10s1+s2+.....+s10=s5×s1s2..,s4,s6..,s10s1+s2+.....+s10
s5×s1s2..,s4,s6..,s10s1+s2+.....+s10=0
Hence answer is D

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