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Question

If S+O2SO2;H=298.2kJ
S02+1/202SO3;H=98.7kJ
SO3+H2OH2SO4;H=130.2kJ
H2+1/202H2O;H=287kJ
Then the enthalpy of formation of H2SO4 at 298 K is?

A
-814.4 kJ
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B
-650.3 kJ
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C
-320.5 kJ
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D
-433.5 kJ
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Solution

The correct option is A -814.4 kJ
S+O2SO2ΔH1=298.2kJ ...(I)
SO2+12O2SO3ΔH2=98.7kJ ...(II)
SO3+H2OH2SO4ΔH3=130.2kJ ...(III)
H2+12O2H2OΔH4=287kJ ...(IV)
we have to calculate ΔH7 of H2SO4
we have to calculate for
H2+S+2O2H2SO4 ...(V)
we can get (V) by (IV)+(I)+(II)+(III)
ΔG7=ΔH1+ΔH2+ΔH3+ΔH4
=814.4kJ

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