If S- O 2 - SO 2 - H-398-2kJ - SO 2 - 1 - 2 O 2 - SO 3 - H-98-7kJ SO 3 - H 2 O- H 2 SO 4 - H-130-2kJ - H 2 - 1 - 2 O 2 - H 2 O- H-227-3kJThe enthalpy of formation of sulphuric acid at 298 K will be-

The correct option is C 854.4 kJ S+O_2 → SO_2 Δ H_1= 398 .2 kJ SO_2+12O_2 → SO_3 Δ H_2^2 98.7 kJ SO_3+H_2O → H_2SO_3 Δ H_3= 13 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Introduction

If S+ O 2 →...

Question

If $S + O_{2} \to {S O}_{2}; △ H = - 398.2 k J : {S O}_{2} + \frac{1}{2} O_{2} \to {S O}_{3}; △ H = - 98.7 k J$
${S O}_{3} + H_{2} O \to H_{2} {S O}_{4}; △ H = - 130.2 k J : H_{2} + \frac{1}{2} O_{2} \to H_{2} O, △ H = - 227.3 k J$
The enthalpy of formation of sulphuric acid at 298 K will be:

-854.4 kJ

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

-754.4 kJ

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-650.3 kJ

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-433.7 kJ

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

S + O_{2} ⟶ S O_{2}; Δ H = - 398.2 k J : S O_{2} + \frac{1}{2} O_{2} ⟶ S O_{3}; Δ H = - 98.7 k J

S O_{3} + H_{2} O ⟶ H_{2} S O_{4}; Δ H = - 130.2 k J : H_{2} + \frac{1}{2} O_{2} ⟶ H_{2} O_{3}; Δ H = - 227.3 k J

298 K

S + O_{2} \to S O_{2}; Δ H = - 398.2 k J; S O_{2} + \frac{1}{2} O_{2} \to S O_{3}; Δ H = - 98.7 k J

S O_{2} + H_{2} O \to H_{2} S O_{4}; Δ H = - 130.2 k J; H_{2} + \frac{1}{2} O_{2} \to H_{2} O; Δ H = - 227.3 k J

298

S + O_{2} \to S O_{2}; Δ H = - 298.2 k J

S O_{2} + \frac{1}{2} O_{2} \to S O_{3}; Δ H = - 98.7 k J

S O_{3} + H_{2} O \to H_{2} S O_{4}; Δ H = - 130.2 k J

H_{2} + \frac{1}{2} O_{2} \to H_{2} O; Δ H = - 227.3 k J

H_{2} S O_{4}

298

S + O_{2} \to {S O}_{2}; △ H = - 298.2 k J

{S 0}_{2} + 1 / 20_{2} \to {S O}_{3}; △ H = - 98.7 k J

S O_{3} + H_{2} O \to H_{2} {S O}_{4}; △ H = - 130.2 k J

H_{2} + 1 / 20_{2} \to H_{2} O; △ H = - 287 k J

H_{2} {S O}_{4}

S + O_{2} \to {S O}_{2}; Δ H = - 298.2 k J

{S O}_{2} + \frac{1}{2} O_{2} \to S O_{3}; Δ H = - 98.7 k J

{S O}_{3} + H_{2} O \to H_{2} {S O}_{4}; Δ H = - 130.2 k J

H_{2} + \frac{1}{2} O_{2} \to H_{2} O; Δ H = - 227.3 k J

H_{2} {S O}_{4}

Join BYJU'S Learning Program