If S p - q - r - p - q - r is a compund statement- then S - p - - q - - r isA- - S p - q - r B- S p - q - r C- p - q - r D- p - q - r

The correct option is C p ∨ (q ∧ r) S(p,q,r)= ∼ p ∨∼(q ∨ r) S( p, q, r)= ∼(∼ p) ∨∼(∼ q ∨∼ r) = p ∨∼(∼(q ∧ r)) = p ∨ (q ∧ r) ...

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Negation

If S p , q , ...

Question

If S(p,q,r)= $\sim p \lor \sim (q \lor r)$ is a compund statement, then S(~p,~q,~r) is

~S (p,q,r)

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S(p,q,r)

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$p \lor (q \land r)$

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$p \lor (q \lor r)$

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Solution

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Similar questions

Negation of the statement $\sim p \to (q \lor r)$ is

The dual of statement $p \lor (q \land r) \equiv (p \lor q) \land (p \lor r)$ is

q \lor \sim (p \land r)

p, q, r

p \Rightarrow (q \lor r)

\sim p \to (q \lor r)

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