Question

# If S0 for H2, Cl2 and HCL are 0.13, 0.22 and 0.19 kJK-1mol-1 respectively. The total change in standard entropy for th2e reaction, H2+Cl2→2HCl40 J K-1mol-130 J K-1mol-160 J K-1mol-120 J K-1mol-1

Solution

## The correct option is B 30 J K-1mol-1∆S = Sp - SR(2×0.19) - 0.13 - 0.22 = 0.03 KJK-1mol-1 =30 K-1mol-1

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