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Question

If S1 is the sum of an arithmetic progression of 'n' odd number of terms and S2 the sum of the terms of the series in odd places, then S1S2=

(a) 2nn+1

(b) nn+1

(c) n+12n

(d) n+1n

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Solution

In the given problem, we are given as the sum of an A.P of ā€˜nā€™ odd number of terms and the sum of the terms of the series in odd places.

We need to find

Now, let a1, a2ā€¦. an be the n terms of A.P

Where n is odd

Let d be the common difference of the A.P

Then,

And be the sum of the terms of the places in odd places,

Where, number of terms =

Common difference = 2d

So,

Now,

Thus,

Therefore, the correct option is (a).


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