If Sameer moves from point A having position vector 2 -4 -2 k- to point B having position vector 6 -8 -3 k- what is his displacement vector-A- 3 -3 k-B- 4 -4 -k-C- 4 -4 -k-D- 3 -3 k-

The correct option is B 4î+4ĵ+ k̂From definition, the displacement vector (S) = r_B r_A where, r represents position vector. Hence, nbsp; S= (6î+8ĵ+ 3k̂) ( ...

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Standard XII

Physics

Subtraction of a Vector

If Sameer mov...

Question

If Sameer moves from point $A$ having position vector $2^i + 4^j + 2^k$ to point $B$ having position vector $6^i + 8^j + 3^k$ , what is his displacement vector?

3^i +^j - 3^k

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4^i + 4^j +^k

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4^i - 4^j -^k

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3^i -^j + 3^k

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Solution

The correct option is B $4^i + 4^j +^k$
From definition,
the displacement vector ( $\to S$ ) = ${\to r}_{B} - {\to r}_{A}$
where, $\to r$ represents position vector.
Hence,
$\to S = (6^i + 8^j + 3^k) - (2^i + 4^j + 2^k)$
$= 4^i + 4^j +^k$

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Similar questions

Q. If Sameer moves from point

A

having position vector

2^i + 4^j + 2^k

to point

B

having position vector

6^i + 8^j + 3^k

, what is his displacement vector?

If a displacement vector of $A B$ is $^i +^j + 2^k$ and point $A$ having a position vector $2^i + 5^j + 6^k$ , then find the position vector of $B$ ?

Q. Constant forces

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6^i +^j - 3^k

Q. A unit vector parallel to the resultant of the vectors

\to A =^i + 4^j - 2^k

and

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Q. The position vectors of the points

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If Sameer moves from point A having position vector 2^i+4^j+2^k to point B having position vector 6^i+8^j+3^k, what is his displacement vector?

The correct option is B 4^i+4^j+^kFrom definition, the displacement vector (→S) = →rB−→rA where, →r represents position vector. Hence, →S=(6^i+8^j+3^k)−(2^i+4^j+2^k) =4^i+4^j+^k

If Sameer moves from point $A$ having position vector $2^i + 4^j + 2^k$ to point $B$ having position vector $6^i + 8^j + 3^k$ , what is his displacement vector?

The correct option is B $4^i + 4^j +^k$
From definition,
the displacement vector ( $\to S$ ) = ${\to r}_{B} - {\to r}_{A}$
where, $\to r$ represents position vector.
Hence,
$\to S = (6^i + 8^j + 3^k) - (2^i + 4^j + 2^k)$
$= 4^i + 4^j +^k$