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Question

If sec2θ=4xy(x+y)2 is true, then which of the following is true? (xy)

A
x+y=0
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B
x=y,x0
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C
x=y
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D
xy
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Solution

The correct option is B x=y,x0
Given sec2θ=4xy(x+y)2

We know, sec2θ1
4xy(x+y)21
4xy(x+y)2
x22xy+y20
(xy)20

Now, (xy)2<0 is not possible
xy=0
x=y and x0

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