If $sec 2 A = cos e c (A - 42),$ where $2 A$ is a measure of acute angle then the value of A is ...............

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Solution

The correct option is B 48
$sec 2 A = c o s e c (A - 42)$
$c o s e c (90 - 2 A) = c o s e c (A - 42) [c o s e c (90 - θ^{o}) = sec θ]$
$90 - 2 A = A - 42$
$A = 48$ .

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