If sec(4A) = cosec(A−20∘), where 4A is an acute angle, then what is the value of A?
110∘
22∘
55∘
44∘
Given, sec(4A) = cosec(A−20∘) ⟹cosec(90−4A)=cosec(A−20∘) [∵secA=cosec(90∘−A)]
⟹90∘−4A=A−20∘
⟹90∘+20∘=A+4A
⟹5A=110∘ ⟹A=22∘
If sec4A = cosec (A – 20o), where 4A is an acute angle.
Find the value of A.