If sec(4A)=cosec(A−20°), where 4A is an acute angle, then what is the value of A?
Given: sec(4A)=cosec(A−20°) cosec(90−4A)=cosec(A−20∘).....(∵secA=cosec(90∘−A))
⟹90∘−4A=A−20∘
⟹90∘+20∘=A+4A ⟹110∘=5A
⟹A=22∘
If sec4A = cosec (A – 20o), where 4A is an acute angle.
Find the value of A.