Question

If sec 5 $\theta$ = cosec$\theta$,find a value of $\theta$

Answer 1

cosec$\theta$ = sec $({90}^{\circ }-\theta )$

sec 5$\theta$ = sec $({90}^{\circ }-\theta )$

5$\theta$ = ${90}^{\circ }-\theta$ i.e. 6$\theta$ = ${90}^{\circ }$

$\theta$ = ${15}^{\circ }$