Question

If sec 5A = cosec(A - ${30}^{\circ }$) and 5A is acute angle then find the value of A in degrees.

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Answer 1

cosec(${90}^{\circ }$ - 5A) = cosec(A - ${30}^{\circ }$)

${90}^{\circ }$- 5A = A - ${30}^{\circ }$

6A = ${120}^{\circ }$

A = ${20}^{\circ }$