Sec6A=cosec(A+6) cosec(90−6A)=cosec(A+6) 90−6A=A+6 7A=84 A=12
If sec 2A=cosec(A−42∘), where 2A is an acute angle, find the value of A.
If sec 2A = cosec (A − 42o),where 2A is an acute angle, find the value of A.