Question

If $\sec A=\frac{13}{12}$ and A is acute, then find the value of $\cot A$ $,cosecA$.

Answer 1

$\sec \theta =\frac{13}{12}\frac{1}{\cos A}=\frac{13}{12}\Rightarrow \cos A=\frac{12}{13}\therefore \cot A=\frac{12}{5}\csc A=\frac{13}{5}$