If -tan-tan-sec - Find -

The correct option is C cosβ .cosγ cosα .sinβ .sinγcosα .cosβ βγ #160; + tanβtanγ #160; = α ⇒β #160; = α #160; tanβtanγγ ⇒β #1 ...

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Trigonometric Ratios for Sum of Two Angles

If βγ+tanβt...

Question

If $sec β sec γ + tan β tan γ = s e c α$ . Find $sec β$

\frac{sec α cos γ}{1 + sin β sin γ}

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\frac{sec α cos γ}{2 + sin β sin α}

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\frac{cos α cos γ}{1 + sin β sin γ}

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\frac{cos β . cos γ - cos α . sin β . s i n γ}{cos α . cos β}

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