If -tan-x- then -a x 2-1 xb x 2-12 xc x 2-12 xd x 2-1 x

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Calculating Heights and Distances

If θ+tanθ=x, ...

Question

If sec θ + tan θ = x, then sec θ =

(a) $\frac{x^{2} + 1}{x}$
(b) $\frac{x^{2} + 1}{2 x}$
(c) $\frac{x^{2} - 1}{2 x}$
(d) $\frac{x^{2} - 1}{x}$

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Solution

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Similar questions

secθ + tanθ = x

tanθ =

\frac{x^{2} + 1}{x}

\frac{x^{2} - 1}{x}

\frac{x^{2} + 1}{2 x}

\frac{x^{2} - 1}{2 x}

θ = x + \frac{1}{4 x}

x, \frac{1}{x}

2 x, \frac{1}{2 x}

- 2 x, \frac{1}{2 x}

- \frac{1}{x}, x

If $s e c θ + t a n θ = x, t h e n s e c θ =$

x = x + \frac{1}{4 x}

x, \frac{1}{x}

2 x, \frac{1}{2 x}

- 2 x, \frac{1}{2 x}

- \frac{1}{x}, x

If $3 x = sec θ, \frac{3}{x} = tan θ$ , then find the value of $x^{2} - \frac{1}{x^{2}}$

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