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Question

If secθ=a+14a then secθ+tanθ=

A
a
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B
2a
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C
3a
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D
4a
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Solution

The correct option is B 2a
secθ+tanθ=secθ+sec2θ1=a+14a+(a+14a)21=a+14a+a14a+a14a=2a

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