Question

If $\sec \theta =\frac{25}{7},$ then find the value of $\tan \theta$?

Answer 1

Given $sec\theta =\frac{25}{7}=\frac{H}{B}$

Using Pythagoras theorem

$H^2=P^2+B^2$

$(25{)}^2=P^2+(7{)}^2$.

$625=P^2+49$

$P^2=625-49$

$P^2=576$

$P=\sqrt{576}$

$P=24cm$

$\therefore tan\theta =\frac{P}{B}=\frac{24}{7}$