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Question

If secθ = 1 14, then tan θ2 =


A

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B

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C

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D

\frac{1}{9}

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Solution

The correct option is A


Given that secθ = 54

secθ = 1+tan2(θ2)1tan2(θ2) 54 = 1+tan2(θ2)1tan2(θ2)

55tan2(θ2)=4+4tan2(θ2)

9tan2(θ2) = 1 tan(θ2) = 13.


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