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Question

If sec θ+tan θ=1 then one root of equation a(bc)x2+b(ca)x+c(ab)=0 is

A
tanθ
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B
secθ
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C
sinθ
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D
none of these
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Solution

The correct option is B secθ
sec θ+tan θ=1.......(1)
We have that
sec2θtan2θ=1
secθtanθ=1........(2)
from (1) and (2)
Secθ=1
a(bc)x2+b(ca)x+c(ab)=0
abx(x1)ac(x21)+bc(x1)=0
x=1=secθ

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