If (secθ - tanθ) = 13, the value of (secθ + tanθ) is:
1
2
3
4
We know that , sec2θ - tan2θ = 1
Therefore, (secθ + tanθ) (secθ - tanθ) = 1
Since, (secθ - tanθ) = 13
Thus, (secθ + tanθ) = 3