Question

If $(sec\theta -tan\theta )=\frac{1}{3}$, the value of;$(sec\theta +tan\theta )$ is:

• A. 1
• B. 2
• C. 3
• D. 4

Answer 1

The correct option is C

3

We know that , $se{c}^2\theta -ta{n}^2\theta =1$

Therefore, $(sec\theta +tan\theta )(sec\theta -tan\theta )=1$

Since, $(sec\theta -tan\theta )=\frac{1}{3}$

Thus $(sec\theta +tan\theta )=3$