If secθ=x+14x then prove that secθ+tanθ=2x or, 12x
Open in App
Solution
secθ=x+14x Lets take secθ+tanθ=p→1 (∵same value p) ⇒(secθ+tanθ)×secθ−tanθsecθ−tanθ=p ⇒sec2θ−tan2θsecθ−tanθ=p ⇒1secθ−tanθ=p ⇒secθ−tanθ=1p→2 1+2 2secθ=p+1pWe know that secθ=x+14x 2(x+14x)=p+1p So p=2x or 12x (both values are satisfied)