If sec2A = cosec(A $-$ 42 $°$ ), where 2A is an acute angle, then find the value of A. [CBSE2008]

Open in App

Solution

We have,

$\sec 2 A = cosec (A - 42 °) \Rightarrow cosec (90 ° - 2 A) = cosec (A - 42 °) Comparing both sides, we get 90 ° - 2 A = A - 42 ° \Rightarrow 2 A + A = 90 ° + 42 ° \Rightarrow 3 A = 132 ° \Rightarrow A = \frac{132 °}{3} ∴ A = 44 °$
Hence, the value of A is $44 °$ .

Suggest Corrections

Similar questions

If sec 2A = cosec $(A - 42^{o})$ ,where 2A is an acute angle, find the value of A.

sec 2 A = cosec (A - 42^{\circ})

2 A

A

sec 2 A = cos e c (A - 42),

2 A

If $s e c 2 A = c o s e c (A - 42^{\circ})$ , where 2A is an acute angle, find the value of A.

sec 2 A

csc (A

42^{\circ}

2 A

A

Join BYJU'S Learning Program