if sectheta=cos^2theta then find the value of sin^4theta +2sin^3theta+sin^2theta

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∣ ∣ ∣ ∣ ∣ \begin{matrix} 1 + {sin}^{2} θ & {sin}^{2} θ & s i n^{2} θ c o s^{2} θ & 1 + c o s^{2} θ & c o s^{2} θ 4 sin 4 θ & 4 sin 4 θ & 1 + 4 sin 4 θ \end{matrix} ∣ ∣ ∣ ∣ ∣ = 0

sin 4 θ

f (θ) = {sin}^{4} θ + {cos}^{2} θ

f (θ)

Δ_{1} = ∣ ∣ ∣ ∣ \begin{matrix} x & sin θ & cos θ - sin θ & - x & 1 cos θ & 1 & x \end{matrix} ∣ ∣ ∣ ∣

Δ_{2} = ∣ ∣ ∣ ∣ \begin{matrix} x & sin 2 θ & cos 2 θ - sin 2 θ & - x & 1 cos 2 θ & 1 & x \end{matrix} ∣ ∣ ∣ ∣

x \neq 0

θ \in (0, \frac{π}{2})

the question given below is of matrix :-

If A=[cos2theta sin2theta]

[-sin2theta cos2theta] find A^2

sec θ + tan θ = p

tan θ

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