If set A has 3 elements and set B has 4 elements, then number of injective functions that can be defined from A to B is
A
144
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B
12
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C
24
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D
64
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Solution
The correct option is C24 The total number of injective function's from set A containing 3 elements to set B containing 4 elements is equal to the total number of arrangements of 4 by taking 3 at a time =4P3=24.