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Question

If sin1(xx22+x34x48+...)=π6, where |x|<2, then the value of x is

A
23
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B
32
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C
23
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D
32
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Solution

The correct option is A 23
We have,
sin1(xx22+x34x48+....)=π6

sin1⎜ ⎜ ⎜ ⎜x1(x2)⎟ ⎟ ⎟ ⎟=π6 [s=a1r]

sin1(2x2+x)=π6

2x2+x=sinπ62x2+x=12

4x=2+x3x=2x=23

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