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Question

If sin1x=π5 for some x ϵ(1,1), then the value of cos1x is
[IIT 1992]


A

3π10

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B

5π10

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C

7π10

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D

9π10

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Solution

The correct option is A

3π10


sin1x+cos1x=π2cos1x=π2sin1x=π2π5=3π10.


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