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Question

If sin1x+sin1y+sin1z=3π2, then xy +yx -xz =

A
\N
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B
1
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C
1 or -1
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D
None
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Solution

The correct option is B 1
sin1x+sin1y+sin1z=3π2sin1x=sin1y=sin1z=π2[π2sin1xπ2]
x=y=z=1xy+yzxz=1+11=1

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