If sin-1x - sin-1y-sin-1z -3 -2- then xy -yx -xz -

Sin^ 1x + sin^ 1y+sin^ 1z =3 π/2 ⇒ sin^ 1x =sin^ 1y =sin^ 1z =π/2 [ ∵ π/2≤ sin^ 1x ≤π/2 ] ⇒ x=y=z=1 ⇒ xy+yz xz =1+1 1 =1 ...

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Domain and Range of Basic Inverse Trigonometric Functions

If sin-1x + s...

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If $s i n^{- 1} x + s i n^{- 1} y + s i n^{- 1} z = \frac{3 π}{2}$ , then xy +yx -xz =

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