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Question

If sin1x+sin1y+sin1z=π2,thenx2+y2+z2+2xyz=
 
  1. 0
  2. 1
  3. -1
  4. None


Solution

The correct option is B 1
Given expression
cos11x2+cos11y2=π2sin1z
 cos1[(1x2)(1y2){1(1x2)}{1(1y2)}]=cos1z
 (1x2)(1y2)xy=z
 (1x2)(1y2)=(xy+z)2
 x2+y2+z2+2xyz=1

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