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Question

If sin1x=y, then which one of the following is correct?


a) 0yπ
b) π2yπ2
c) 0<y<π
d) π2<y<π2

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Solution


As range of sin1x is [π2,π2], therefore π2yπ2.
Hence, the correct option is (b) is correct as per the range of sine function.


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