If sin−1x=y, then which one of the following is correct?
a) 0≤y≤π b) −π2≤y≤π2 c) 0<y<π d) −π2<y<π2
As range of sin−1x is [−π2,π2], therefore −π2≤y≤π2. Hence, the correct option is (b) is correct as per the range of sine function.
Find the value of if sin−1 x = y, then
(A) (B)
(C) (D)