If sin2 -1-4- then the general solution of -

The correct option is B nπ ± π/6 nbsp;sin ^ 2 θ nbsp; = 1 / 4 =( 1 / 2 nbsp;) nbsp;^ 2 ⇒θ =nπ±π nbsp;/ 6 ...

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Standard XII

Mathematics

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If sin2 θ=1...

Question

If $s i n^{2} θ = \frac{1}{4}$ , then the general solution of $θ$

2 n π \pm (- 1)^{n} \frac{π}{6}

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\frac{n π}{2} \pm (- 1)^{n} \frac{π}{6}

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n π \pm \frac{π}{6}

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2 n π \pm \frac{π}{6}

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Solution

The correct option is B $n π \pm \frac{π}{6}$
${sin}^{2} θ = \frac{1}{4} = {(\frac{1}{2})}^{2} \Rightarrow θ = n π \pm \frac{π}{6}$

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If sin2θ=14, then the general solution of θ

The correct option is B nπ±π6sin2θ=14=(12)2⇒θ=nπ±π6

If $s i n^{2} θ = \frac{1}{4}$ , then the general solution of $θ$

The correct option is B $n π \pm \frac{π}{6}$
${sin}^{2} θ = \frac{1}{4} = {(\frac{1}{2})}^{2} \Rightarrow θ = n π \pm \frac{π}{6}$