If sin 3 -cos-60 where - and -6 are acute angles- the value of - is

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Standard Values of Trigonometric Ratios

If sin 3 θ=co...

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If sin 3 θ = cos(θ - 6⁰) where θ and (θ - 6) are acute angles, the value of θ is

90^o

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30^o

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60^o

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24^o

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If cos $3 θ = c o s θ - 6^{o}$ ,where 3 $θ$ and $θ - 6^{o}$ are acute angles, find the value of $θ$

(θ + 36^{\circ}) = c o s θ

θ

θ + 36^{\circ}

θ

(θ + 36^{\circ}) = c o s θ

θ

θ + 36^{\circ}

θ

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