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Question

If sin 3θ=sinθ,then the general value of θ is

A
2nπ,(2n+1)π3
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B
nπ,(2n+1)π4
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C
nπ,(2n+1)π3
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D
None of these
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Solution

The correct option is C nπ,(2n+1)π4
sin3θ=sinθ
3θ=mπ+(1)mθ
For (m) even i.e, m=2n then θ=2nπ2=nπ
For (m) odd i.e, m=2n+1 then θ=(2n+1)π4.
Hence, the answer is nπ,(2n+1)π4.

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