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Question

If sin4θ+1sin4θ=194,θnπ,nZ, then the value(s) of (2cosec θcotθcosθ) can be

A
2
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B
2
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C
4
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D
4
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Solution

The correct options are
C 4
D 4
2cosec θcotθcosθ=2cos2θsinθ=1+sin2θsinθ=sinθ+1sinθ

Now,
sin4θ+1sin4θ=194(sin2θ+1sin2θ)22=194sin2θ+1sin2θ=14 (sin2θ>0)(sinθ+1sinθ)22=14sinθ+1sinθ=±42cosec θcotθcosθ=±4

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