If - sin6-cos6-1-3u2-3u4- then - u-

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Trigonometric Ratios of Allied Angles

If : sin6θ+...

Question

If : ${sin}^{6} θ + {cos}^{6} θ = 1 - 3 u^{2} + 3 u^{4}$ , then : $u =$

sec θ

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tan θ

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sin θ

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cos θ

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Solution

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sin θ + cos θ = \frac{a}{2},

{sin}^{6} θ + {cos}^{6} θ

\sin^{6} θ + \cos^{6} θ = \frac{4 - 3 {(x^{2} - 1)}^{2}}{4}

\frac{tan θ}{1 - tan θ} - \frac{cot θ}{1 - cot θ} = \frac{cos θ + sin θ}{cos θ - sin θ}

\frac{sin θ - cos θ + 1}{sin θ + cos θ - 1} = \frac{m}{sec θ - tan θ},

m

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