Consider the given equation.
sin(7ϕ+9∘)=cos2ϕ
sin(7ϕ+9∘)=sin(90∘−2ϕ)
7ϕ+9∘=90∘−2ϕ
9ϕ=81∘
ϕ=9∘
If sin2θ+sin2ϕ=12 and cos2θ+cos2ϕ=32, then cos2(θ−ϕ)=