Question

If $sin({90}^0-\theta )=\frac{3}{7}$, then $cos\theta$

• A. $\frac{7}{3}$
• B. $\frac{3}{7}$
• C. $\frac{-7}{3}$
• D. $\frac{-3}{7}$

Answer 1

The correct option is B $\frac{3}{7}$

$\sin ({90}^o-\theta )=\frac{3}{7}$

We know,

$\sin ({90}^o-\theta )=\cos \theta$

Hence, $\cos \theta =\frac{3}{7}$