If sin α and cos α are the roots of the equation ax2+bx+c=0, then
a2 - b2 + 2ac = 0
Sum of the roots = −ba
Product of the roots = ba
sin α+cos α=−ba.......(1)sin α×cos α=ca.......(2)Squaring(1) gives(sin α+cos α)2=(−ba)2(sin α)2+(cos α)2+2 sin α×cos α=(ba)2⇒1+2×(ca)=(ba)2Multiplying with a2 gaves a2+2ac=b2⇒a2−b2+2ac=0