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General Solution of sin theta = sin alpha

If sinα and c...

Question

If sin α and cos α are the roots of the equations ax²+ bx + c = 0, then b² =

(a) a² − 2ac
(b) a² + 2ac
(c) a² − ac
(d) a² + ac

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Solution

The given quadric equation is , and are roots of given equation.

And,

Then, as we know that sum of the roots

…. (1)

And the product of the roots

…. (2)

Squaring both sides of equation (1) we get

Putting the value of , we get

Putting the value of , we get

Therefore, the value of

Thus, the correct answer is

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Q. If sin θ and cos θ are the roots of the equation ax² – bx + c = 0, then a, b and c satisfy the relation
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s i n α + s i n β = a

c o s α + c o s β = b,

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If $α, β$ are the roots of the equation a $x^{2}$ +2bx +c = 0 and $α + δ$ , $β + δ$ are the roots of A $x^{2}$ + 2Bx + C= 0 , then $\frac{b^{2} - a c}{B^{2} - A C}$ =

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General Solution of sin theta = sin alpha

Standard XII Mathematics

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