Question

If $\sin A=\cos {33}^{\circ }$ find $A$

Answer 1

We have $\sin A=\cos ({90}^{\circ }-A)$. So,
$\cos ({90}^{\circ }-A)=\cos {33}^{\circ }\Rightarrow {90}^{\circ }-A={33}^{\circ }$
$\therefore A={90}^{\circ }-{33}^{\circ }={57}^{\circ }$