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Question

If sinA+cosA=p and secA+cosecA=q , then prove that:
q(p21)=2p.

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Solution

sinA+cosA=p....(1)

squaring both sides
(sinA+cosA)2=p2

sin2A+cos2A+2sinAcosA=p2 [sin2A+cos2A=1]

1+2sinAcosA=p2

sinAcosA=p212....(2)

secA+cosec A=q

1cosA+1sinA=q

(taking LCM)
sinA+cosAsinAcosA=q (from eq. 1 & 2)

pp212=q

2p=q(p21)

Hence proved

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