If $s i n A = c o s A$ , then $2 t a n^{2} A - 2 s e c^{2} A + 5 =$ ___

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Solution

The correct option is C
3

$s i n A = c o s A$

$∴ t a n A = 1$

$A = 45^{\circ}$

$2 t a n^{2} A - 2 s e c^{2} A + 5$

$= 2 (1) - 2 (\sqrt{2})^{2} + 5$

= 2 - 4 + 5

= 3

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Similar questions

(i) (s i n^{2} A c o s^{2} B - c o s^{2} A s i n^{2} B) = (s i n^{2} A - s i n^{2} B)

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