Question

If Sin A +Cosec A= 2, then $si{n}^2$A + $cose{c}^2$A =__

Answer 1

Given, sin A + cosec A = 2
Therefore, $(sinA+cosecA{)}^2$ = 4
$si{n}^2$A + $cose{c}^2$A + 2sin A cosec A = 4

$si{n}^2$A + $cose{c}^2$A + 2 sin A x $\frac{1}{sinA}$ = 4

So, $si{n}^2$A + $cose{c}^2$A = 2.