CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If sinA=1213,cosB=35,0<A<π2, π<B<3π2, then the value of sin(A+B) is

A
3365
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
163
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
5665
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
6365
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 5665
sinA=1213, 0<A<π2cosA=513cosB=35, π<B<3π2sinB=45
Now,
sin(A+B)=sinAcosB+cosAsinBsin(A+B)=1213×35513×45sin(A+B)=5665

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Operations on Sets
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon