Question

If $\sin A=\frac{12}{13}$. Then the value of $\tan \frac{A}{2}$

Answer 1

$\sin A=\frac{12}{13}$

$\Rightarrow \frac{2\tan \frac{A}{2}}{1+{\tan }^2\frac{A}{2}}=\frac{12}{3}$

$\Rightarrow 6{\tan }^2\frac{A}{2}–13\tan \frac{A}{2}+6=0$

$\Rightarrow (\tan \frac{A}{2}-12)(\tan \frac{A}{2}-1)=0$

$\therefore \tan \frac{A}{2}=1,12$ Ans