Question

If sin A = $\frac{3}{4}$ , calculate cos A and tan A.

Answer 1

$sin$ $A$ = $\frac{3}{4}$

By pythagoras theorem,

$(Hypotenuse{)}^2=(Base{)}^2+(Perpendicular{)}^2$

Therefore,

$(4{)}^2=(B{)}^2+(3{)}^2$

$(B{)}^2=7$

$B$ = $\sqrt{7}$

Therefore,

cos A = $\frac{\sqrt{7}}{4}$ and tan A = $\frac{3}{\sqrt{7}}$